int 1x {6 (logx) ^2+ 7logx + 2 } d x =

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Click here:point_up_2:to get an answer to your question :writing_hand:6 the value of int frac e 5 log x

$int 1x {6 (logx) ^2+ 7logx + 2 } d x =$

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$int 1x {6 (logx) ^2+ 7logx + 2 } d x =$

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$int 1x {6 (logx) ^2+ 7logx + 2 } d x =$

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$int 1x {6 (logx) ^2+ 7logx + 2 } d x =$

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$int 1x {6 (logx) ^2+ 7logx + 2 } d x =$

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$int 1x {6 (logx) ^2+ 7logx + 2 } d x =$

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$int 1x {6 (logx) ^2+ 7logx + 2 } d x =$

Evaluate the following integral : ∫1/(x{6(logx)^2+7logx+2})dx - Sarthaks eConnect

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